What is the solution for x(d^2y)/(dx^2)+2(dy)/(dx)=0 ?

The solution for x(d^2y)/(dx^2)+2(dy)/(dx)=0 is y=c_{1}+(c_{2})/x

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x(d^2y)/(dx^2)+2(dy)/(dx)=0

x \frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} = 0

y = c_{1} + \frac{c _{2}}{x}

Solution steps

x \frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} = 0

Solve linear ODE:

y = c_{1} + \frac{c _{2}}{x}

y = c_{1} + \frac{c _{2}}{x}

\int_{3}^{5} \frac{x}{x ^{2} + 6 x + 13} d x

x \to 0 lim (\frac{- 2 x ( x + 2 )}{4 x ^{2} - 3 x - 7})

\frac{d}{d x} (3 x^{3} + 2)

f (x) = - 4 - 5 x^{2}, (- 5, - 129)

\int sin^{3} (y) cos^{6} (y) d y

What is the solution for x(d^2y)/(dx^2)+2(dy)/(dx)=0 ?
The solution for x(d^2y)/(dx^2)+2(dy)/(dx)=0 is y=c_{1}+(c_{2})/x