What is the solution for y^{''}+6y^'+10=0 ?

The solution for y^{''}+6y^'+10=0 is y=c_{1}+c_{2}e^{-6t}-(5t)/3

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y^{''}+6y^'+10=0

y^{^{''}} + 6 y^{^{'}} + 10 = 0

y = c_{1} + c_{2} e^{- 6 t} - \frac{5 t}{3}

Solution steps

y^{''} (t) + 6 y^{'} (t) + 10 = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 6 t} - \frac{5 t}{3}

y = c_{1} + c_{2} e^{- 6 t} - \frac{5 t}{3}

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What is the solution for y^{''}+6y^'+10=0 ?
The solution for y^{''}+6y^'+10=0 is y=c_{1}+c_{2}e^{-6t}-(5t)/3