What is the derivative of x^2+8x+14 ?

The derivative of x^2+8x+14 is 2x+8

What is the first derivative of x^2+8x+14 ?

The first derivative of x^2+8x+14 is 2x+8

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derivative of

x^{2} + 8 x + 14

2 x + 8

Solution steps

\frac{d}{d x} (x^{2} + 8 x + 14)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (8 x) + \frac{d}{d x} (14)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (14) = 0

= 2 x + 8 + 0

Simplify

= 2 x + 8

\frac{d}{d x} (3^{1 - 3 x})

\int e^{- s t} (t sin (t)) d t

\int sin^{2} (t) cos^{4} (t) d t

y = 3 x + 4

\frac{d}{d x} (\frac{2 x}{( x + 1 )})

What is the derivative of x^2+8x+14 ?
The derivative of x^2+8x+14 is 2x+8
What is the first derivative of x^2+8x+14 ?
The first derivative of x^2+8x+14 is 2x+8