What is the derivative of y=sqrt(x-1) ?

The derivative of y=sqrt(x-1) is 1/(2sqrt(x-1))

What is the first derivative of y=sqrt(x-1) ?

The first derivative of y=sqrt(x-1) is 1/(2sqrt(x-1))

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derivative of

y = x - 1

\frac{1}{2 x - 1}

Solution steps

\frac{d}{d x} (x - 1)

Apply the chain rule:

\frac{1}{2 x - 1} \frac{d}{d x} (x - 1)

= \frac{1}{2 x - 1} \frac{d}{d x} (x - 1)

\frac{d}{d x} (x - 1) = 1

= \frac{1}{2 x - 1} \cdot 1

Simplify

= \frac{1}{2 x - 1}

(2 x + 1)^{2}

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(2 y^{2} + 3 x y - 2 y + 6 x) d x + x (x + 2 y - 1) d y = 0

\int 18 x - 24 d x

\frac{\partial}{\partial x} (60 e^{- 0.07 x})

What is the derivative of y=sqrt(x-1) ?
The derivative of y=sqrt(x-1) is 1/(2sqrt(x-1))
What is the first derivative of y=sqrt(x-1) ?
The first derivative of y=sqrt(x-1) is 1/(2sqrt(x-1))