What is (\partial)/(\partial x)(4x^3y^3-1) ?

The answer to (\partial)/(\partial x)(4x^3y^3-1) is 12x^2y^3

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(\partial)/(\partial x)(4x^3y^3-1)

\frac{\partial}{\partial x} (4 x^{3} y^{3} - 1)

12 x^{2} y^{3}

Solution steps

\frac{\partial}{\partial x} (4 x^{3} y^{3} - 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 x^{3} y^{3}) - \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (4 x^{3} y^{3}) = 12 y^{3} x^{2}

\frac{\partial}{\partial x} (1) = 0

= 12 y^{3} x^{2} - 0

Simplify

= 12 x^{2} y^{3}

\int 4 cos (3 x) d x

\int 7 t^{4} d t

\int \frac{x ^{2}}{x + 1} d x

\frac{0.07 e ^{x}}{sin ( x )}

k = 1 \sum \infty \frac{k}{7 ^{k}}

What is (\partial)/(\partial x)(4x^3y^3-1) ?
The answer to (\partial)/(\partial x)(4x^3y^3-1) is 12x^2y^3