What is the derivative of 9e^x+8/(\sqrt[3]{x}) ?

The derivative of 9e^x+8/(\sqrt[3]{x}) is 9e^x-8/(3x^{4/3)}

What is the first derivative of 9e^x+8/(\sqrt[3]{x}) ?

The first derivative of 9e^x+8/(\sqrt[3]{x}) is 9e^x-8/(3x^{4/3)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (9 e^{x} + \frac{8}{3 x})

9 e^{x} - \frac{8}{3 x ^{\frac{4}{3}}}

Solution steps

\frac{d}{d x} (9 e^{x} + \frac{8}{3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 e^{x}) + \frac{d}{d x} (\frac{8}{3 x})

\frac{d}{d x} (9 e^{x}) = 9 e^{x}

\frac{d}{d x} (\frac{8}{3 x}) = - \frac{8}{3 x ^{\frac{4}{3}}}

= 9 e^{x} - \frac{8}{3 x ^{\frac{4}{3}}}

\frac{d}{d t} (10 t e^{- 5 t})

ln (1 - 4 y), 0

x y^{^{'}} = y + x^{2} + y^{2}

\int - 5 x^{3} d x

x \to 0 lim (\frac{sin ( k t )}{t})

What is the derivative of 9e^x+8/(\sqrt[3]{x}) ?
The derivative of 9e^x+8/(\sqrt[3]{x}) is 9e^x-8/(3x^{4/3)}
What is the first derivative of 9e^x+8/(\sqrt[3]{x}) ?
The first derivative of 9e^x+8/(\sqrt[3]{x}) is 9e^x-8/(3x^{4/3)}