What is the d/(dt)(2cos(t)+2sin(t)) ?

The d/(dt)(2cos(t)+2sin(t)) is -2sin(t)+2cos(t)

What is the first d/(dt)(2cos(t)+2sin(t)) ?

The first d/(dt)(2cos(t)+2sin(t)) is -2sin(t)+2cos(t)

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\frac{d}{d t} (2 cos (t) + 2 sin (t))

- 2 sin (t) + 2 cos (t)

Solution steps

\frac{d}{d t} (2 cos (t) + 2 sin (t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (2 cos (t)) + \frac{d}{d t} (2 sin (t))

\frac{d}{d t} (2 cos (t)) = - 2 sin (t)

\frac{d}{d t} (2 sin (t)) = 2 cos (t)

= - 2 sin (t) + 2 cos (t)

F (x) = (9 x^{6} + 4 x^{3})^{4}

y^{^{''}} - 2 y^{^{'}} - 3 y = 16 x^{2} e^{- x}

y^{^{''}} + 4 y^{^{'}} + 5 y = e^{x} + 5 x

\frac{1}{( s ^{2} + 4 ) \cdot s ^{2} \cdot e}

\frac{\partial}{\partial x} (sec^{2} (x))

What is the d/(dt)(2cos(t)+2sin(t)) ?
The d/(dt)(2cos(t)+2sin(t)) is -2sin(t)+2cos(t)
What is the first d/(dt)(2cos(t)+2sin(t)) ?
The first d/(dt)(2cos(t)+2sin(t)) is -2sin(t)+2cos(t)