What is (\partial)/(\partial y)(2x+3y-4) ?

The answer to (\partial)/(\partial y)(2x+3y-4) is 3

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(\partial)/(\partial y)(2x+3y-4)

\frac{\partial}{\partial y} (2 x + 3 y - 4)

3

Solution steps

\frac{\partial}{\partial y} (2 x + 3 y - 4)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x) + \frac{\partial}{\partial y} (3 y) - \frac{\partial}{\partial y} (4)

\frac{\partial}{\partial y} (2 x) = 0

\frac{\partial}{\partial y} (3 y) = 3

\frac{\partial}{\partial y} (4) = 0

= 0 + 3 - 0

Simplify

= 3

\frac{\partial}{\partial y} (e^{x} y^{3} + 2 y e^{2 x})

\frac{d y}{d x} = - \frac{y}{10}

f (x) = x^{2} - 8, (2, - 4)

\int tan (x) 1 + sec^{4} (x) d x

sin (a x)

What is (\partial)/(\partial y)(2x+3y-4) ?
The answer to (\partial)/(\partial y)(2x+3y-4) is 3