What is the derivative of 3+6cos(3t) ?

The derivative of 3+6cos(3t) is -18sin(3t)

What is the first derivative of 3+6cos(3t) ?

The first derivative of 3+6cos(3t) is -18sin(3t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

3 + 6 cos (3 t)

- 18 sin (3 t)

Solution steps

\frac{d}{d t} (3 + 6 cos (3 t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (3) + \frac{d}{d t} (6 cos (3 t))

\frac{d}{d t} (3) = 0

\frac{d}{d t} (6 cos (3 t)) = - 18 sin (3 t)

= 0 - 18 sin (3 t)

Simplify

= - 18 sin (3 t)

- \frac{1}{2} t^{4} + 48 t^{2}

f (x) = \frac{1}{x}, at x = 2

\frac{d}{d x} (\frac{d y}{d x}) + 4 y = 2 sin (2 x)

2 x^{^{''}} + 12 x^{^{'}} + 50 x = 0

80 \cdot 2 2^{\frac{t}{20}}

What is the derivative of 3+6cos(3t) ?
The derivative of 3+6cos(3t) is -18sin(3t)
What is the first derivative of 3+6cos(3t) ?
The first derivative of 3+6cos(3t) is -18sin(3t)