What is the tangent of f(x)=pi^{3x+3},\at x=2 ?

The tangent of f(x)=pi^{3x+3},\at x=2 is y=3pi^9ln(pi)x+pi^9-6pi^9ln(pi)

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tangent of f(x)=pi^{3x+3},\at x=2

tangent of

f (x) = π^{3 x + 3}, at x = 2

y = 3 π^{9} ln (π) x + π^{9} - 6 π^{9} ln (π)

Solution steps

Find the tangent point:

(2, π^{9})

Find the slope of

f (x) = π^{3 x + 3} : \frac{df ( x )}{d x} = 3 ln (π) π^{3 x + 3}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3 π^{9} ln (π)

Find the line with slope m=

3 π^{9} ln (π)

and passing through

(2, π^{9}) : y = 3 π^{9} ln (π) x + π^{9} - 6 π^{9} ln (π)

y = 3 π^{9} ln (π) x + π^{9} - 6 π^{9} ln (π)

121 y^{^{''}} + 88 y^{^{'}} + 12 y = 0

4 + cot^{2} (x)

x + 5

\int_{0}^{N} e^{- s t} e^{5 t} d t

x \to 2 lim (- x + 6)

What is the tangent of f(x)=pi^{3x+3},\at x=2 ?
The tangent of f(x)=pi^{3x+3},\at x=2 is y=3pi^9ln(pi)x+pi^9-6pi^9ln(pi)