What is the derivative of h^2+7h+40 ?

The derivative of h^2+7h+40 is 2h+7

What is the first derivative of h^2+7h+40 ?

The first derivative of h^2+7h+40 is 2h+7

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derivative of

h^{2} + 7 h + 40

2 h + 7

Solution steps

\frac{d}{d h} (h^{2} + 7 h + 40)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d h} (h^{2}) + \frac{d}{d h} (7 h) + \frac{d}{d h} (40)

\frac{d}{d h} (h^{2}) = 2 h

\frac{d}{d h} (7 h) = 7

\frac{d}{d h} (40) = 0

= 2 h + 7 + 0

Simplify

= 2 h + 7

y^{^{'}} = x y^{8}

\int_{0}^{x} x d x

f (x) = \frac{5}{2 5 x + 4}, at x = 9

\frac{\partial}{\partial x} (sin (π (2 x - 4 y)))

\frac{\partial}{\partial x} (arcsin (\frac{x}{y}))

What is the derivative of h^2+7h+40 ?
The derivative of h^2+7h+40 is 2h+7
What is the first derivative of h^2+7h+40 ?
The first derivative of h^2+7h+40 is 2h+7