What is the derivative of f(x)=ln(1/x) ?

The derivative of f(x)=ln(1/x) is -1/x

What is the first derivative of f(x)=ln(1/x) ?

The first derivative of f(x)=ln(1/x) is -1/x

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derivative of

f (x) = ln (\frac{1}{x})

- \frac{1}{x}

Solution steps

\frac{d}{d x} (ln (\frac{1}{x}))

Simplify

ln (\frac{1}{x}) : - ln (x)

= \frac{d}{d x} (- ln (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (ln (x))

Apply the common derivative:

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= - \frac{1}{x}

\frac{d y}{d t} = y - 2 t

\int \frac{x}{x + 8} d x

x \to 2 lim (\frac{1}{2 - 5 x})

\frac{d}{d t} (e^{4 t})

What is the derivative of f(x)=ln(1/x) ?
The derivative of f(x)=ln(1/x) is -1/x
What is the first derivative of f(x)=ln(1/x) ?
The first derivative of f(x)=ln(1/x) is -1/x