What is implicit (dy)/(dx),x^3+y^3=36 ?

The answer to implicit (dy)/(dx),x^3+y^3=36 is (dy)/(dx)=-(x^2)/(y^2)

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implicit (dy)/(dx),x^3+y^3=36

implicit derivative

\frac{d y}{d x}, x^{3} + y^{3} = 36

\frac{d y}{d x} = - \frac{x ^{2}}{y ^{2}}

Solution steps

x^{3} + y^{3} = 36

Treat

y

y (x)

Differentiate both sides:

3 x^{2} + 3 y^{2} \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{x ^{2}}{y ^{2}}

\frac{d y}{d x} = - \frac{x ^{2}}{y ^{2}}

(0, 1), (1, - 3)

x \to - \infty lim (x - 4)

\frac{2}{s ^{3} ( s ^{2} + 9 )}

\int (\frac{1}{x ^{6}}) d x

\frac{\partial}{\partial x} (0.1 x \cdot y)

What is implicit (dy)/(dx),x^3+y^3=36 ?
The answer to implicit (dy)/(dx),x^3+y^3=36 is (dy)/(dx)=-(x^2)/(y^2)