What is laplacetransform f(t)=5+4*\delta(t) ?

The answer to laplacetransform f(t)=5+4*\delta(t) is 5/s+4

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laplacetransform f(t)=5+4*\delta(t)

laplace transform

f (t) = 5 + 4 \cdot δ (t)

\frac{5}{s} + 4

Solution steps

L {5 + 4 δ (t)}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {5} + 4 L {δ (t)}

L {5} : \frac{5}{s}

L {δ (t)} : 1

= \frac{5}{s} + 4 \cdot 1

Refine

\frac{5}{s} + 41 : \frac{5}{s} + 4

= \frac{5}{s} + 4

\frac{d}{d x} (ln (1 + sin (x)))

\frac{d}{d x} ((f (x) (6 x))^{2} - 2)

x \to 0 + lim (2 + ln (x))

\int (cos (3 x))^{3} d x

\frac{d}{d x} (- e^{4 x})

What is laplacetransform f(t)=5+4*\delta(t) ?
The answer to laplacetransform f(t)=5+4*\delta(t) is 5/s+4