What is the derivative of sin(x)*tan(x) ?

The derivative of sin(x)*tan(x) is sin(x)(1+sec^2(x))

What is the first derivative of sin(x)*tan(x) ?

The first derivative of sin(x)*tan(x) is sin(x)(1+sec^2(x))

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derivative of

sin (x) \cdot tan (x)

sin (x) (1 + sec^{2} (x))

Solution steps

\frac{d}{d x} (sin (x) tan (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = sin (x), g = tan (x)

= \frac{d}{d x} (sin (x)) tan (x) + \frac{d}{d x} (tan (x)) sin (x)

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= cos (x) tan (x) + sec^{2} (x) sin (x)

Simplify

cos (x) tan (x) + sec^{2} (x) sin (x) : sin (x) (1 + sec^{2} (x))

= sin (x) (1 + sec^{2} (x))

\int - 8 e^{- 8 x} d x

\int \frac{1}{( 9 + x ^{2} ) ^{2}} d x

y (1 + x^{2}) y^{^{'}} - x (5 + y^{2}) = 0

\int_{0}^{1} 6 e^{- 2 x} d x

e^{8}

What is the derivative of sin(x)*tan(x) ?
The derivative of sin(x)*tan(x) is sin(x)(1+sec^2(x))
What is the first derivative of sin(x)*tan(x) ?
The first derivative of sin(x)*tan(x) is sin(x)(1+sec^2(x))