What is the solution for f^'(x)=(8x^5-6x^9)/(x^4) ?

The solution for f^'(x)=(8x^5-6x^9)/(x^4) is f(x)=4x^2-x^6+c_{1}

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f^'(x)=(8x^5-6x^9)/(x^4)

f^{^{'}} (x) = \frac{8 x ^{5} - 6 x ^{9}}{x ^{4}}

f (x) = 4 x^{2} - x^{6} + c_{1}

Solution steps

f^{'} (x) = \frac{8 x ^{5} - 6 x ^{9}}{x ^{4}}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int \frac{8 x ^{5} - 6 x ^{9}}{x ^{4}} d x

\int \frac{8 x ^{5} - 6 x ^{9}}{x ^{4}} d x = 4 x^{2} - x^{6} + c_{1}

f (x) = 4 x^{2} - x^{6} + c_{1}

\frac{d}{d x} (ln (1 + e^{2 x}))

x \to - 1 lim (\frac{x ^{2} - x}{x})

\int_{2}^{\infty} \frac{1}{x ^{2} - 1} d x

\frac{d y}{d x} + y = y^{2}, y (0) = 2

\int \frac{y}{4} d y

What is the solution for f^'(x)=(8x^5-6x^9)/(x^4) ?
The solution for f^'(x)=(8x^5-6x^9)/(x^4) is f(x)=4x^2-x^6+c_{1}