What is the first derivative of e^{0x} ?

The first derivative of e^{0x} is 0

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derivative of e^{0x}

\frac{d}{d x} (e^{0 x})

0

Solution steps

\frac{d}{d x} (e^{0 \cdot x})

e^{0 \cdot x} = 1

= \frac{d}{d x} (1)

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

f (x) = \frac{π x}{2}

\frac{d}{d x} (64 x - \frac{x ^{3}}{3})

\frac{d}{d x} (ln (6 x^{2} + 3 x))

x \to 1 lim ((x - 2)^{2})

n = 1 \sum \infty (\frac{1}{2})^{n + 1}