What is the integral from 4 to 6 of x^3 ?

The integral from 4 to 6 of x^3 is 260

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integral from 4 to 6 of x^3

\int_{4}^{6} x^{3} d x

260

Solution steps

\int_{4}^{6} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{4}^{6}

= [\frac{x ^{4}}{4}]_{4}^{6}

Compute the boundaries:

260

= 260

y = (k (x)^{2} + x^{2})^{4} (x + k (x))

\frac{\partial}{\partial x} (x^{2} y + y ln (x z^{3}))

\int 3 x^{4} + \frac{7}{4} x^{5} d x

y^{^{'}} + y + 4 cos (x) = 0

\frac{d}{d x} (\frac{( x + 1 )}{( x - 1 )})

What is the integral from 4 to 6 of x^3 ?
The integral from 4 to 6 of x^3 is 260