What is the derivative of y=2ln(3)+1/2 ln(x^2+1) ?

The derivative of y=2ln(3)+1/2 ln(x^2+1) is x/(x^2+1)

What is the first derivative of y=2ln(3)+1/2 ln(x^2+1) ?

The first derivative of y=2ln(3)+1/2 ln(x^2+1) is x/(x^2+1)

Popular >

derivative of

y = 2 ln (3) + \frac{1}{2} ln (x^{2} + 1)

\frac{x}{x ^{2} + 1}

Solution steps

\frac{d}{d x} (2 ln (3) + \frac{1}{2} ln (x^{2} + 1))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 ln (3)) + \frac{d}{d x} (\frac{1}{2} ln (x^{2} + 1))

\frac{d}{d x} (2 ln (3)) = 0

\frac{d}{d x} (\frac{1}{2} ln (x^{2} + 1)) = \frac{x}{x ^{2} + 1}

= 0 + \frac{x}{x ^{2} + 1}

Simplify

= \frac{x}{x ^{2} + 1}

\frac{d}{d x} (2 x (4 - x^{2})^{\frac{1}{2}})

\int se x^{2} x d x

\int sec^{2} (x) + 7 d x

\int k y d y

\frac{d}{d x} (\frac{3 x ^{7} - 7 x + 11}{2 x ^{3}})

What is the derivative of y=2ln(3)+1/2 ln(x^2+1) ?
The derivative of y=2ln(3)+1/2 ln(x^2+1) is x/(x^2+1)
What is the first derivative of y=2ln(3)+1/2 ln(x^2+1) ?
The first derivative of y=2ln(3)+1/2 ln(x^2+1) is x/(x^2+1)