What is the solution for 4xy^'+2y=10x^6 ?

The solution for 4xy^'+2y=10x^6 is y=(5x^6)/(13)+(c_{1})/(sqrt(x))

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4xy^'+2y=10x^6

4 x y^{^{'}} + 2 y = 10 x^{6}

y = \frac{5 x ^{6}}{13} + \frac{c _{1}}{x}

Solution steps

4 x y^{'} (x) + 2 y = 10 x^{6}

Solve linear ODE:

y = \frac{5 x ^{6}}{13} + \frac{c _{1}}{x}

y = \frac{5 x ^{6}}{13} + \frac{c _{1}}{x}

\int \frac{x ^{3} + x ^{2}}{x ^{5}} d x

(x^{4} - 3 x)^{2}

13 x

\int \frac{2 x}{e ^{8 x}} d x

y = - 3 x^{2} - x

What is the solution for 4xy^'+2y=10x^6 ?
The solution for 4xy^'+2y=10x^6 is y=(5x^6)/(13)+(c_{1})/(sqrt(x))