What is the integral of a/(a^2+x^2) ?

The integral of a/(a^2+x^2) is arctan(x/a)+C

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integral of a/(a^2+x^2)

\int \frac{a}{a ^{2} + x ^{2}} d x

arctan (\frac{x}{a}) + C

Solution steps

\int \frac{a}{a ^{2} + x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= a \cdot \int \frac{1}{a ^{2} + x ^{2}} d x

Apply Integral Substitution

= a \cdot \int \frac{1}{a ( u ^{2} + 1 )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= a \frac{1}{a} \cdot \int \frac{1}{u ^{2} + 1} d u

Use the common integral:

\int \frac{1}{u ^{2} + 1} d u = arctan (u)

= a \frac{1}{a} arctan (u)

Substitute back

u = \frac{x}{a}

= a \frac{1}{a} arctan (\frac{x}{a})

Simplify

a \frac{1}{a} arctan (\frac{x}{a}) : arctan (\frac{x}{a})

= arctan (\frac{x}{a})

Add a constant to the solution

= arctan (\frac{x}{a}) + C

\int \frac{1}{5 x + 4} d x

n = 1 \sum \infty \frac{8 n}{7 - 4 n}

\frac{d}{d x} (3 tan (2^{- x}))

x (1 + y^{2}) d x + y (1 + x^{2}) d y = 0

x \to 0 lim (x (1))

What is the integral of a/(a^2+x^2) ?
The integral of a/(a^2+x^2) is arctan(x/a)+C