What is the derivative of x^e+e^x ?

The derivative of x^e+e^x is ex^{e-1}+e^x

What is the first derivative of x^e+e^x ?

The first derivative of x^e+e^x is ex^{e-1}+e^x

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\frac{d}{d x} (x^{e} + e^{x})

e x^{e - 1} + e^{x}

Solution steps

\frac{d}{d x} (x^{e} + e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{e}) + \frac{d}{d x} (e^{x})

\frac{d}{d x} (x^{e}) = e x^{e - 1}

\frac{d}{d x} (e^{x}) = e^{x}

= e x^{e - 1} + e^{x}

\frac{d}{d x} (7 x y)

\frac{d}{d x} (arcsec (2 x + 1))

\int x 1 + 3 x d x

\frac{\partial}{\partial x} (x - 2 y^{2} - 2 z^{2})

\int_{1}^{9} \frac{x - 1}{x} d x

What is the derivative of x^e+e^x ?
The derivative of x^e+e^x is ex^{e-1}+e^x
What is the first derivative of x^e+e^x ?
The first derivative of x^e+e^x is ex^{e-1}+e^x