What is area y=tan(7x),y=2sin(7x) ?

The answer to area y=tan(7x),y=2sin(7x) is diverges

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area y=tan(7x),y=2sin(7x)

area

y = tan (7 x), y = 2 sin (7 x)

diverges

Solution steps

Apply the area formula:

\int_{- \frac{5 π}{21}}^{0} ∣ tan (7 x) - 2 sin (7 x) ∣ d x

Solve

\int_{- \frac{5 π}{21}}^{0} ∣ tan (7 x) - 2 sin (7 x) ∣ d x :

diverges

The area is:

= diverges

x \frac{d y}{d x} + y = y^{2}

x^{2} + x

\int_{- 2}^{2} (x^{3}) d x

\frac{d}{d x} (\frac{54}{x})

\int \frac{2 x - 5}{x ^{3} + 4 x ^{2} + 4 x} d x

What is area y=tan(7x),y=2sin(7x) ?
The answer to area y=tan(7x),y=2sin(7x) is diverges