What is the derivative of \sqrt[8]{8x^7-10} ?

The derivative of \sqrt[8]{8x^7-10} is (7x^6)/((8x^7-10)^{7/8)}

What is the first derivative of \sqrt[8]{8x^7-10} ?

The first derivative of \sqrt[8]{8x^7-10} is (7x^6)/((8x^7-10)^{7/8)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (8 8 x^{7} - 10)

\frac{7 x ^{6}}{( 8 x ^{7} - 10 ) ^{\frac{7}{8}}}

Solution steps

\frac{d}{d x} (8 8 x^{7} - 10)

Apply the chain rule:

\frac{1}{8 ( 8 x ^{7} - 10 ) ^{\frac{7}{8}}} \frac{d}{d x} (8 x^{7} - 10)

= \frac{1}{8 ( 8 x ^{7} - 10 ) ^{\frac{7}{8}}} \frac{d}{d x} (8 x^{7} - 10)

\frac{d}{d x} (8 x^{7} - 10) = 56 x^{6}

= \frac{1}{8 ( 8 x ^{7} - 10 ) ^{\frac{7}{8}}} \cdot 56 x^{6}

Simplify

\frac{1}{8 ( 8 x ^{7} - 10 ) ^{\frac{7}{8}}} \cdot 56 x^{6} : \frac{7 x ^{6}}{( 8 x ^{7} - 10 ) ^{\frac{7}{8}}}

= \frac{7 x ^{6}}{( 8 x ^{7} - 10 ) ^{\frac{7}{8}}}

\frac{d y}{d x} = arctan (- 6 x)

y = (\frac{2 x + 1}{3 x - 1})^{4}

\int e^{- 6 x} d x

n = 1 \sum \infty (x - 3)^{n}

x \to 1 lim (\frac{4}{x - 1})

What is the derivative of \sqrt[8]{8x^7-10} ?
The derivative of \sqrt[8]{8x^7-10} is (7x^6)/((8x^7-10)^{7/8)}
What is the first derivative of \sqrt[8]{8x^7-10} ?
The first derivative of \sqrt[8]{8x^7-10} is (7x^6)/((8x^7-10)^{7/8)}