What is (\partial}{\partial {K}}(L^{1/2)/K ^{1/2}) ?

The answer to (\partial}{\partial {K}}(L^{1/2)/K ^{1/2}) is (L^{1/2})/(2{K)^{1/2}}

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(\partial}{\partial {K}}(L^{1/2)/K ^{1/2})

\frac{\partial}{\partial K} (L^{\frac{1}{2}} K^{\frac{1}{2}})

\frac{L ^{\frac{1}{2}}}{2 K ^{\frac{1}{2}}}

Solution steps

\frac{\partial}{\partial K} (L^{\frac{1}{2}} K^{\frac{1}{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= L^{\frac{1}{2}} \frac{\partial}{\partial K} (K^{\frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= L^{\frac{1}{2}} \frac{1}{2} K^{\frac{1}{2} - 1}

Simplify

L^{\frac{1}{2}} \frac{1}{2} K^{\frac{1}{2} - 1} : \frac{L ^{\frac{1}{2}}}{2 K ^{\frac{1}{2}}}

= \frac{L ^{\frac{1}{2}}}{2 K ^{\frac{1}{2}}}

x \to 4 lim (x + 4)

f (x) = 4 x - 7

\int_{0}^{4} y d y

\frac{d}{d x} ((2 x + 5)^{4})

\frac{5}{s ^{2} + 2 s + 5}

What is (\partial}{\partial {K}}(L^{1/2)/K ^{1/2}) ?
The answer to (\partial}{\partial {K}}(L^{1/2)/K ^{1/2}) is (L^{1/2})/(2{K)^{1/2}}