What is the integral from-1 to 3 of-x^2 ?

The integral from-1 to 3 of-x^2 is -28/3

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integral from-1 to 3 of-x^2

\int_{- 1}^{3} - x^{2} d x

- \frac{28}{3}

Decimal

- 9.33333 \dots

Solution steps

\int_{- 1}^{3} - x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{- 1}^{3} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 1}^{3}

= - [\frac{x ^{3}}{3}]_{- 1}^{3}

Compute the boundaries:

\frac{28}{3}

= - \frac{28}{3}

\frac{d}{d x} (\frac{6}{5 x ^{3}})

\int sin^{2} (\frac{x}{2}) cos (\frac{x}{2}) d x

f (x) = (6 x + 5) (x^{3} - 2)

x \to + 3 lim (0)

- \frac{y}{x + 5 e}

What is the integral from-1 to 3 of-x^2 ?
The integral from-1 to 3 of-x^2 is -28/3