What is the derivative of f(x)=x^4-12x^3+3 ?

The derivative of f(x)=x^4-12x^3+3 is 4x^3-36x^2

What is the first derivative of f(x)=x^4-12x^3+3 ?

The first derivative of f(x)=x^4-12x^3+3 is 4x^3-36x^2

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derivative of

f (x) = x^{4} - 12 x^{3} + 3

4 x^{3} - 36 x^{2}

Solution steps

\frac{d}{d x} (x^{4} - 12 x^{3} + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (12 x^{3}) + \frac{d}{d x} (3)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (12 x^{3}) = 36 x^{2}

\frac{d}{d x} (3) = 0

= 4 x^{3} - 36 x^{2} + 0

Simplify

= 4 x^{3} - 36 x^{2}

\int 8 sin^{3} (x) cos (x) d x

\frac{\partial}{\partial x} (x y ln (x y))

f (x) = 3 x, at x = 64

\int 2 x^{2} + 5 d x

\frac{x d y}{d x} = - y + 2 x^{2} y, y (1) = 1

What is the derivative of f(x)=x^4-12x^3+3 ?
The derivative of f(x)=x^4-12x^3+3 is 4x^3-36x^2
What is the first derivative of f(x)=x^4-12x^3+3 ?
The first derivative of f(x)=x^4-12x^3+3 is 4x^3-36x^2