What is the tangent of f(x)=e^{2x},\at x= 1/2 ln(3) ?

The tangent of f(x)=e^{2x},\at x= 1/2 ln(3) is y=6x+3-3ln(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=e^{2x},\at x= 1/2 ln(3)

tangent of

f (x) = e^{2 x}, at x = \frac{1}{2} ln (3)

y = 6 x + 3 - 3 ln (3)

Solution steps

Find the tangent point:

(\frac{1}{2} ln (3), 3)

Find the slope of

f (x) = e^{2 x} : \frac{df ( x )}{d x} = e^{2 x} \cdot 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6

Find the line with slope m=

6

and passing through

(\frac{1}{2} ln (3), 3) : y = 6 x + 3 - 3 ln (3)

y = 6 x + 3 - 3 ln (3)

(\frac{t ^{3}}{t ^{6} + 7})^{2}

\int \frac{x}{16 + x ^{2}} d x

x \to 3 lim (2 x + ∣ x - 3 ∣)

x \to 7 lim (\frac{x + 5}{x + 9})

x^{2} y^{^{''}} + x y^{^{'}} + 9 y = 10 x

What is the tangent of f(x)=e^{2x},\at x= 1/2 ln(3) ?
The tangent of f(x)=e^{2x},\at x= 1/2 ln(3) is y=6x+3-3ln(3)