What is the tangent of 2x^3+3x^2-12x+8 ?

The tangent of 2x^3+3x^2-12x+8 is y=(6a_{0}^2+6a_{0}-12)x-4a_{0}^3-3a_{0}^2+8

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tangent of 2x^3+3x^2-12x+8

tangent of

2 x^{3} + 3 x^{2} - 12 x + 8

y = (6 a_{0}^{2} + 6 a_{0} - 12) x - 4 a_{0}^{3} - 3 a_{0}^{2} + 8

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 2 a_{0}^{3} + 3 a_{0}^{2} - 12 a_{0} + 8)

Find the slope of

y = 2 x^{3} + 3 x^{2} - 12 x + 8 : \frac{d y}{d x} = 6 x^{2} + 6 x - 12

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6 a_{0}^{2} + 6 a_{0} - 12

Find the line with slope m=

6 a_{0}^{2} + 6 a_{0} - 12

and passing through

(a_{0}, 2 a_{0}^{3} + 3 a_{0}^{2} - 12 a_{0} + 8) : y = (6 a_{0}^{2} + 6 a_{0} - 12) x - 4 a_{0}^{3} - 3 a_{0}^{2} + 8

y = (6 a_{0}^{2} + 6 a_{0} - 12) x - 4 a_{0}^{3} - 3 a_{0}^{2} + 8

x \to \infty lim (e^{n x})

\frac{d}{d x} (\frac{2 x}{3 x - 2})

\int x (x + 1) d x

\frac{d y}{d x}, e^{\frac{x}{y}} = x - y

y^{^{''}} + 16.67 y^{^{'}} + 10000 y = 0

What is the tangent of 2x^3+3x^2-12x+8 ?
The tangent of 2x^3+3x^2-12x+8 is y=(6a_{0}^2+6a_{0}-12)x-4a_{0}^3-3a_{0}^2+8