What is the derivative of (1-x^2^2) ?

The derivative of (1-x^2^2) is -4x(1-x^2)

What is the first derivative of (1-x^2^2) ?

The first derivative of (1-x^2^2) is -4x(1-x^2)

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\frac{d}{d x} ((1 - x^{2})^{2})

- 4 x (1 - x^{2})

Solution steps

\frac{d}{d x} ((1 - x^{2})^{2})

Apply the chain rule:

2 (1 - x^{2}) \frac{d}{d x} (1 - x^{2})

= 2 (1 - x^{2}) \frac{d}{d x} (1 - x^{2})

\frac{d}{d x} (1 - x^{2}) = - 2 x

= 2 (1 - x^{2}) (- 2 x)

Simplify

= - 4 x (1 - x^{2})

\frac{d y}{d x} = \frac{y + 3}{x + 3}

\frac{x ^{3}}{6 x - 3}

3 x^{2} + 4, [1, 2]

\int \frac{k}{x ( ln ( x ) ) ^{b}} d x

x \to 0 + lim (\frac{e ^{4 x}}{3 x})

What is the derivative of (1-x^2^2) ?
The derivative of (1-x^2^2) is -4x(1-x^2)
What is the first derivative of (1-x^2^2) ?
The first derivative of (1-x^2^2) is -4x(1-x^2)