What is the derivative of 3x^2-8x ?

The derivative of 3x^2-8x is 6x-8

What is the first derivative of 3x^2-8x ?

The first derivative of 3x^2-8x is 6x-8

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\frac{d}{d x} (3 x^{2} - 8 x)

6 x - 8

Solution steps

\frac{d}{d x} (3 x^{2} - 8 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (8 x)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (8 x) = 8

= 6 x - 8

\frac{d y}{d x}, 2 x y = 0

\frac{d}{d x} (\frac{π ^{2}}{x ^{2} + 4 x})

3 x y + x^{2} + y^{2}

y^{^{''}} + 3 y^{^{'}} = (4 t + 4) sin (4 t)

(x^{3} + y^{3}) d x - 3 x y^{2} d y = 0

What is the derivative of 3x^2-8x ?
The derivative of 3x^2-8x is 6x-8
What is the first derivative of 3x^2-8x ?
The first derivative of 3x^2-8x is 6x-8