What is the derivative of f(x)=2x^2+8x ?

The derivative of f(x)=2x^2+8x is 4x+8

What is the first derivative of f(x)=2x^2+8x ?

The first derivative of f(x)=2x^2+8x is 4x+8

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derivative of

f (x) = 2 x^{2} + 8 x

4 x + 8

Solution steps

\frac{d}{d x} (2 x^{2} + 8 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (8 x)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (8 x) = 8

= 4 x + 8

n = 1 \sum \infty 2 (- \frac{1}{2})^{n}

\frac{d}{d t} (1 + t)

\int 8 x e^{x} d x

\int 5 csc^{4} (x) cot^{6} (x) d x

\frac{d}{d x} (\frac{( x + 1 ) ^{2}}{x - 1})

What is the derivative of f(x)=2x^2+8x ?
The derivative of f(x)=2x^2+8x is 4x+8
What is the first derivative of f(x)=2x^2+8x ?
The first derivative of f(x)=2x^2+8x is 4x+8