What is the derivative of x^3+x+2 ?

The derivative of x^3+x+2 is 3x^2+1

What is the first derivative of x^3+x+2 ?

The first derivative of x^3+x+2 is 3x^2+1

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\frac{d}{d x} (x^{3} + x + 2)

3 x^{2} + 1

Solution steps

\frac{d}{d x} (x^{3} + x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d x}{d x} + \frac{d}{d x} (2)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d x}{d x} = 1

\frac{d}{d x} (2) = 0

= 3 x^{2} + 1 + 0

Simplify

= 3 x^{2} + 1

\int x - 2 cos (x) d x

\frac{d}{d x} (- \frac{x ^{3}}{y ^{3}})

\frac{d}{d x} (\frac{27}{x})

12 x

\int (5 x + 2)^{- 3} d x

What is the derivative of x^3+x+2 ?
The derivative of x^3+x+2 is 3x^2+1
What is the first derivative of x^3+x+2 ?
The first derivative of x^3+x+2 is 3x^2+1