What is the derivative of y=sqrt(2x-x^2) ?

The derivative of y=sqrt(2x-x^2) is (1-x)/(sqrt(2x-x^2))

What is the first derivative of y=sqrt(2x-x^2) ?

The first derivative of y=sqrt(2x-x^2) is (1-x)/(sqrt(2x-x^2))

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derivative of

y = 2 x - x^{2}

\frac{1 - x}{2 x - x ^{2}}

Solution steps

\frac{d}{d x} (2 x - x^{2})

Apply the chain rule:

\frac{1}{2 2 x - x ^{2}} \frac{d}{d x} (2 x - x^{2})

= \frac{1}{2 2 x - x ^{2}} \frac{d}{d x} (2 x - x^{2})

\frac{d}{d x} (2 x - x^{2}) = 2 - 2 x

= \frac{1}{2 2 x - x ^{2}} (2 - 2 x)

Simplify

\frac{1}{2 2 x - x ^{2}} (2 - 2 x) : \frac{1 - x}{2 x - x ^{2}}

= \frac{1 - x}{2 x - x ^{2}}

\frac{\partial}{\partial x} (\frac{10000 x}{y ^{2}})

n = 1 \sum \infty (\frac{8}{5})^{n - 1}

(t^{2} + 1) f^{^{'}} (t) + [f (t)]^{2} + 1 = 0, f (4) = e

\int \frac{x ^{3}}{x} d x

\int_{0}^{2} 5 x^{3} x^{2} + 4 d x

What is the derivative of y=sqrt(2x-x^2) ?
The derivative of y=sqrt(2x-x^2) is (1-x)/(sqrt(2x-x^2))
What is the first derivative of y=sqrt(2x-x^2) ?
The first derivative of y=sqrt(2x-x^2) is (1-x)/(sqrt(2x-x^2))