What is (\partial)/(\partial v)(2usin(v)) ?

The answer to (\partial)/(\partial v)(2usin(v)) is 2ucos(v)

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(\partial)/(\partial v)(2usin(v))

\frac{\partial}{\partial v} (2 u sin (v))

2 u cos (v)

Solution steps

\frac{\partial}{\partial v} (2 u sin (v))

Treat

u

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 u \frac{\partial}{\partial v} (sin (v))

Apply the common derivative:

\frac{\partial}{\partial v} (sin (v)) = cos (v)

= 2 u cos (v)

\frac{d}{d x} (x^{3} - 2 x + 2)

\int \frac{1}{4 x - 2} d x

x \to 3 lim (\frac{2}{x} + 1)

y = 5 x, y = \frac{5}{x}, x = 5

\int_{0}^{1} \frac{x}{e ^{6 x}} d x

What is (\partial)/(\partial v)(2usin(v)) ?
The answer to (\partial)/(\partial v)(2usin(v)) is 2ucos(v)