What is the integral of 5xln(2x) ?

The integral of 5xln(2x) is 5(1/2 x^2ln(2x)-(x^2)/4)+C

Popular >

integral of 5xln(2x)

\int 5 x ln (2 x) d x

5 (\frac{1}{2} x^{2} ln (2 x) - \frac{x ^{2}}{4}) + C

Solution steps

\int 5 x ln (2 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int x ln (2 x) d x

Apply Integration By Parts

: \frac{1}{2} x^{2} ln (2 x) - \int \frac{x}{2} d x

= 5 (\frac{1}{2} x^{2} ln (2 x) - \int \frac{x}{2} d x)

\int \frac{x}{2} d x = \frac{x ^{2}}{4}

= 5 (\frac{1}{2} x^{2} ln (2 x) - \frac{x ^{2}}{4})

Add a constant to the solution

= 5 (\frac{1}{2} x^{2} ln (2 x) - \frac{x ^{2}}{4}) + C

\int \frac{ln ( x ^{15} )}{x} d x

\int \frac{x + 9}{x ^{2} - 6 x + 9} d x

y (\frac{π}{21}) = 2 tan^{2} (7 x)

\frac{d}{d x} (2^{\frac{x}{2}})

\frac{d}{d x} (e^{\frac{- x}{2}})

What is the integral of 5xln(2x) ?
The integral of 5xln(2x) is 5(1/2 x^2ln(2x)-(x^2)/4)+C