What is the integral of sec(x)tan(x)-3e^x ?

The integral of sec(x)tan(x)-3e^x is sec(x)-3e^x+C

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integral of sec(x)tan(x)-3e^x

\int sec (x) tan (x) - 3 e^{x} d x

sec (x) - 3 e^{x} + C

Solution steps

\int sec (x) tan (x) - 3 e^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sec (x) tan (x) d x - \int 3 e^{x} d x

\int sec (x) tan (x) d x = sec (x)

\int 3 e^{x} d x = 3 e^{x}

= sec (x) - 3 e^{x}

Add a constant to the solution

= sec (x) - 3 e^{x} + C

\int_{0}^{5} \frac{w}{w - 2} d w

x \to 0 lim (3 x cos (x))

\int_{5}^{7} \frac{1}{x ^{2} - 1} d x

\frac{d}{d x} (\frac{1 + e ^{x}}{1 - e ^{x}})

\int cos^{2} (\frac{3 π x}{l}) d x

What is the integral of sec(x)tan(x)-3e^x ?
The integral of sec(x)tan(x)-3e^x is sec(x)-3e^x+C