What is (\partial)/(\partial x)(3x^2y+4xz^3) ?

The answer to (\partial)/(\partial x)(3x^2y+4xz^3) is 6yx+4z^3

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(\partial)/(\partial x)(3x^2y+4xz^3)

\frac{\partial}{\partial x} (3 x^{2} y + 4 x z^{3})

6 y x + 4 z^{3}

Solution steps

\frac{\partial}{\partial x} (3 x^{2} y + 4 x z^{3})

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2} y) + \frac{\partial}{\partial x} (4 x z^{3})

\frac{\partial}{\partial x} (3 x^{2} y) = 6 y x

\frac{\partial}{\partial x} (4 x z^{3}) = 4 z^{3}

= 6 y x + 4 z^{3}

y = x^{4} - 4 x^{3} + 2

x \to - 4 lim (\frac{- 1}{x ^{2} - 16})

\int \frac{- e ^{- s t}}{s} d t

\frac{d}{d x} (- 10 sin (10 x) - cos (10 x))

\int ln (9 x) d x

What is (\partial)/(\partial x)(3x^2y+4xz^3) ?
The answer to (\partial)/(\partial x)(3x^2y+4xz^3) is 6yx+4z^3