What is area y=2cos(x),y=6-4cos(x),0<= x<= 2pi ?

The answer to area y=2cos(x),y=6-4cos(x),0<= x<= 2pi is 12pi

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area y=2cos(x),y=6-4cos(x),0<= x<= 2pi

area

y = 2 cos (x), y = 6 - 4 cos (x), 0 \leq x \leq 2 π

12 π

Decimal

37.69911 \dots

Solution steps

Apply the area formula:

\int_{0}^{2 π} ∣ 2 cos (x) - (6 - 4 cos (x)) ∣ d x

Solve

\int_{0}^{2 π} ∣ 2 cos (x) - (6 - 4 cos (x)) ∣ d x : 12 π

The area is:

= 12 π

f (x) = 18 x^{2} - 14 x + 9

\frac{d}{d x} (ln (x^{2} + 2 x + 1))

- 2 x cos (x^{2}) - e^{- x - 2}

y = \frac{4 x ^{4} + 5}{x ^{2}}

\frac{\partial}{\partial x} (4 - 2 x^{2} - y^{2})

What is area y=2cos(x),y=6-4cos(x),0<= x<= 2pi ?
The answer to area y=2cos(x),y=6-4cos(x),0<= x<= 2pi is 12pi