What is the tangent of-2x^2+3 ?

The tangent of-2x^2+3 is y=-4a_{0}x+2a_{0}^2+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of-2x^2+3

tangent of

- 2 x^{2} + 3

y = - 4 a_{0} x + 2 a_{0}^{2} + 3

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 2 a_{0}^{2} + 3)

Find the slope of

y = - 2 x^{2} + 3 : \frac{d y}{d x} = - 4 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 4 a_{0}

Find the line with slope m=

- 4 a_{0}

and passing through

(a_{0}, - 2 a_{0}^{2} + 3) : y = - 4 a_{0} x + 2 a_{0}^{2} + 3

y = - 4 a_{0} x + 2 a_{0}^{2} + 3

\frac{x}{10} - \frac{10}{x}

\frac{d v}{d t} + \frac{3 v}{2} = 9.8

\int 3 x (x + x^{2})^{'} d x

\frac{d y}{d x} = \frac{y}{x} + 5 x + 1

\frac{\partial}{\partial x} (4 y x)