What is the derivative of 6sin(3x) ?

The derivative of 6sin(3x) is 18cos(3x)

What is the first derivative of 6sin(3x) ?

The first derivative of 6sin(3x) is 18cos(3x)

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derivative of

6 sin (3 x)

18 cos (3 x)

Solution steps

\frac{d}{d x} (6 sin (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{d}{d x} (3 x)

= cos (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= 6 cos (3 x) \cdot 3

Simplify

= 18 cos (3 x)

\int (x^{4} - 3)^{2} d x

\frac{d}{d t} (- 2 sin (2 t))

x \to 4 lim (4 x)

\int \frac{ln ( x )}{x x} d x

n = 1 \sum \infty \frac{1}{( n ( n + 2 ) )}

What is the derivative of 6sin(3x) ?
The derivative of 6sin(3x) is 18cos(3x)
What is the first derivative of 6sin(3x) ?
The first derivative of 6sin(3x) is 18cos(3x)