What is the derivative of 9e^{-x}-3e^{-4x} ?

The derivative of 9e^{-x}-3e^{-4x} is -9e^{-x}+12e^{-4x}

What is the first derivative of 9e^{-x}-3e^{-4x} ?

The first derivative of 9e^{-x}-3e^{-4x} is -9e^{-x}+12e^{-4x}

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derivative of

9 e^{- x} - 3 e^{- 4 x}

- 9 e^{- x} + 12 e^{- 4 x}

Solution steps

\frac{d}{d x} (9 e^{- x} - 3 e^{- 4 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 e^{- x}) - \frac{d}{d x} (3 e^{- 4 x})

\frac{d}{d x} (9 e^{- x}) = - 9 e^{- x}

\frac{d}{d x} (3 e^{- 4 x}) = - 12 e^{- 4 x}

= - 9 e^{- x} - (- 12 e^{- 4 x})

Simplify

= - 9 e^{- x} + 12 e^{- 4 x}

\int sec (t) (5 sec (t) + 2 tan (t)) d t

\int_{1}^{5} \frac{x}{2 x - 1} d x

x \to 0 lim (cos (x) + sin (x))

(x + 2)^{2} + (y - 3)^{2} = 37, (4, 2)

\frac{d y}{d x} = \frac{( y ^{2} - 1 )}{x ^{2} - 1}, y (7) = 7

What is the derivative of 9e^{-x}-3e^{-4x} ?
The derivative of 9e^{-x}-3e^{-4x} is -9e^{-x}+12e^{-4x}
What is the first derivative of 9e^{-x}-3e^{-4x} ?
The first derivative of 9e^{-x}-3e^{-4x} is -9e^{-x}+12e^{-4x}