What is the solution for (xy^2+x^3)dx+(y^3+x^2y)dy=0 ?

The solution for (xy^2+x^3)dx+(y^3+x^2y)dy=0 is y=sqrt(-x^2+c_{1)},y=-sqrt(-x^2+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(xy^2+x^3)dx+(y^3+x^2y)dy=0

(x y^{2} + x^{3}) d x + (y^{3} + x^{2} y) d y = 0

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

Solution steps

(x y^{2} + x^{3}) d x + (y^{3} + x^{2} y) d y = 0

Solve separable ODE:

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

\frac{d}{d x} (tan (cos (x)))

\frac{d y}{d x}, y = x

\int \frac{1}{x ^{2} + 2 x} d x

\int (4 - 3 sin (2 x))^{4} cos (2 x) d x

h (a) = 2 x - 5

What is the solution for (xy^2+x^3)dx+(y^3+x^2y)dy=0 ?
The solution for (xy^2+x^3)dx+(y^3+x^2y)dy=0 is y=sqrt(-x^2+c_{1)},y=-sqrt(-x^2+c_{1)}