What is the derivative of x^2-8x+17 ?

The derivative of x^2-8x+17 is 2x-8

What is the first derivative of x^2-8x+17 ?

The first derivative of x^2-8x+17 is 2x-8

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derivative of

x^{2} - 8 x + 17

2 x - 8

Solution steps

\frac{d}{d x} (x^{2} - 8 x + 17)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (8 x) + \frac{d}{d x} (17)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (17) = 0

= 2 x - 8 + 0

Simplify

= 2 x - 8

\int (x^{2} + 5) (x - 3) d x

\frac{x}{x ^{2} + 1}

\int e^{- s t} \cdot t^{2} d t

\int 3 x^{2} - 4 d x

5 x - x^{2}, 2 x, [0, 3]

What is the derivative of x^2-8x+17 ?
The derivative of x^2-8x+17 is 2x-8
What is the first derivative of x^2-8x+17 ?
The first derivative of x^2-8x+17 is 2x-8