What is the solution for y^{''}+2y^'=2x+9-e^{-2x} ?

The solution for y^{''}+2y^'=2x+9-e^{-2x} is y=c_{1}+c_{2}e^{-2x}+(x^2+e^{-2x}x)/2+4x

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y^{''}+2y^'=2x+9-e^{-2x}

y^{^{''}} + 2 y^{^{'}} = 2 x + 9 - e^{- 2 x}

y = c_{1} + c_{2} e^{- 2 x} + \frac{x ^{2} + e ^{- 2 x} x}{2} + 4 x

Solution steps

y^{''} (x) + 2 y^{'} (x) = 2 x + 9 - e^{- 2 x}

Solve linear ODE:

y = c_{1} + c_{2} e^{- 2 x} + \frac{x ^{2} + e ^{- 2 x} x}{2} + 4 x

y = c_{1} + c_{2} e^{- 2 x} + \frac{x ^{2} + e ^{- 2 x} x}{2} + 4 x

\frac{6 s + 4}{s ^{2} + 4 s + 20}

y^{^{'}} + 5 y = e^{- 3 x}

\int sin^{6} (x) cos^{5} (x) d x

\int e^{x} + x^{e} + e + x d x

f (x) = sin (4 x) - cos (3 x)

What is the solution for y^{''}+2y^'=2x+9-e^{-2x} ?
The solution for y^{''}+2y^'=2x+9-e^{-2x} is y=c_{1}+c_{2}e^{-2x}+(x^2+e^{-2x}x)/2+4x