What is the limit as x approaches 0 of x/(x^2+4x) ?

The limit as x approaches 0 of x/(x^2+4x) is 1/4

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limit as x approaches 0 of x/(x^2+4x)

x \to 0 lim (\frac{x}{x ^{2} + 4 x})

\frac{1}{4}

Decimal

0.25

Solution steps

x \to 0 lim (\frac{x}{x ^{2} + 4 x})

Simplify

\frac{x}{x ^{2} + 4 x} : \frac{1}{x + 4}

= x \to 0 lim (\frac{1}{x + 4})

Plug in the value

x = 0

= \frac{1}{0 + 4}

Simplify

= \frac{1}{4}

n = 1 \sum \infty (1 - \frac{3}{n})^{n}

\int (e^{\frac{x}{2}}) d x

\frac{\partial}{\partial x} (2 x yz - y e^{2 x yz})

(3.1) (1.7)

n = 1 \sum \infty (- 3)^{n} x^{n}

What is the limit as x approaches 0 of x/(x^2+4x) ?
The limit as x approaches 0 of x/(x^2+4x) is 1/4