What is the tangent of f(x)=sqrt(7-4x),\at x=-1 ?

The tangent of f(x)=sqrt(7-4x),\at x=-1 is y=-2/(sqrt(11))x+sqrt(11)-2/(sqrt(11))

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tangent of f(x)=sqrt(7-4x),\at x=-1

tangent of

f (x) = 7 - 4 x, at x = - 1

y = - \frac{2}{11} x + 11 - \frac{2}{11}

Solution steps

Find the tangent point:

(- 1, 11)

Find the slope of

f (x) = 7 - 4 x : \frac{df ( x )}{d x} = - \frac{2}{7 - 4 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{2}{11}

Find the line with slope m=

- \frac{2}{11}

and passing through

(- 1, 11) : y = - \frac{2}{11} x + 11 - \frac{2}{11}

y = - \frac{2}{11} x + 11 - \frac{2}{11}

\int 1 + cos (2 x) d x

\frac{d ^{2} y}{d x ^{2}} + 5 \frac{d y}{d x} + 4 y = 0

\frac{d y}{d x} = y^{2} (x + 1)

\int \frac{1}{9 e ^{y} + e ^{- y}} d y

\frac{d}{d x} (\frac{5 x ^{2}}{sin ( x )})

What is the tangent of f(x)=sqrt(7-4x),\at x=-1 ?
The tangent of f(x)=sqrt(7-4x),\at x=-1 is y=-2/(sqrt(11))x+sqrt(11)-2/(sqrt(11))