What is the derivative of f(x)=x+4/x ?

The derivative of f(x)=x+4/x is 1-4/(x^2)

What is the first derivative of f(x)=x+4/x ?

The first derivative of f(x)=x+4/x is 1-4/(x^2)

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derivative of

f (x) = x + \frac{4}{x}

1 - \frac{4}{x ^{2}}

Solution steps

\frac{d}{d x} (x + \frac{4}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (\frac{4}{x})

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

= 1 - \frac{4}{x ^{2}}

2 y^{^{''}} - 4 y^{^{'}} + 3 y = 9 t^{2} + 10

\frac{d}{d x} (3^{3 x + 1})

\int x^{6} y^{2}

x^{2} + 7 x - 4

x \to - \infty lim (6 x^{4})

What is the derivative of f(x)=x+4/x ?
The derivative of f(x)=x+4/x is 1-4/(x^2)
What is the first derivative of f(x)=x+4/x ?
The first derivative of f(x)=x+4/x is 1-4/(x^2)