What is the integral of sech^4(x)tanh(x) ?

The integral of sech^4(x)tanh(x) is -1/4 sech^4(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of sech^4(x)tanh(x)

\int sech^{4} (x) tanh (x) d x

- \frac{1}{4} sech^{4} (x) + C

Solution steps

\int sech^{4} (x) tanh (x) d x

Apply u-substitution

: \int - \frac{1}{4} d u

= \int - \frac{1}{4} d u

Integral of a constant:

\int a d x = a x

= (- \frac{1}{4}) u

Substitute back

u = sech^{4} (x)

= (- \frac{1}{4}) sech^{4} (x)

Simplify

= - \frac{1}{4} sech^{4} (x)

Add a constant to the solution

= - \frac{1}{4} sech^{4} (x) + C

4 x y^{^{'}} + 4 y = 3

x^{5} + 1, x + 1, - 1, 0

5 x - 6 y x^{2} + 1 \frac{d y}{d x} = 0

x \to 2 lim (x^{2} - 3 x + 8)

\int - 2 x^{6} sin (3 x) d x

What is the integral of sech^4(x)tanh(x) ?
The integral of sech^4(x)tanh(x) is -1/4 sech^4(x)+C