What is the solution for y^'+7(tan(7x))y=5cos(7x) ?

The solution for y^'+7(tan(7x))y=5cos(7x) is y=(5x)/(sec(7x))+(c_{1})/(sec(7x))

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y^'+7(tan(7x))y=5cos(7x)

y^{^{'}} + 7 (tan (7 x)) y = 5 cos (7 x)

y = \frac{5 x}{sec ( 7 x )} + \frac{c _{1}}{sec ( 7 x )}

Solution steps

y^{'} (x) + 7 (tan (7 x)) y = 5 cos (7 x)

Solve linear ODE:

y = \frac{5 x}{sec ( 7 x )} + \frac{c _{1}}{sec ( 7 x )}

y = \frac{5 x}{sec ( 7 x )} + \frac{c _{1}}{sec ( 7 x )}

\frac{x ^{5}}{x ^{3}}

\int \frac{5}{x ^{2} x ^{2} - 9} d x

\frac{d}{d x} (x e^{- x^{2} y})

\frac{d ^{2}}{d x ^{2}} (3 x sin (x^{2}))

\int \frac{x}{x - 9} d x

What is the solution for y^'+7(tan(7x))y=5cos(7x) ?
The solution for y^'+7(tan(7x))y=5cos(7x) is y=(5x)/(sec(7x))+(c_{1})/(sec(7x))